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Remove all null and undefined properties from an object

Written byPhuoc Nguyen
Category
Object
Created
20 Apr, 2021
Last updated
15 May, 2023
Contributors
jjswifty
JavaScript version
removeNullUndefined.js
const removeNullUndefined = (obj) => Object.entries(obj).reduce((a, [k, v]) => (v == null ? a : ((a[k] = v), a)), {});

// Or
const removeNullUndefined = (obj) =>
Object.entries(obj)
.filter(([_, v]) => v != null)
.reduce((acc, [k, v]) => ({ ...acc, [k]: v }), {});

// Or
const removeNullUndefined = (obj) => Object.fromEntries(Object.entries(obj).filter(([_, v]) => v != null));
TypeScript version
const removeNullUndefined = <T extends Record<string, any>>(obj: T) =>
Object.entries(obj).reduce((a: any, [k, v]) =>
(v == null ? a : ((a[k] = v), a)), {}) as {
[K in keyof T as T[K] extends null | undefined ? never : K]: T[K]
};

// Or
const removeNullUndefined = <T extends Record<string, any>>(obj: T) =>
Object.entries(obj)
.filter(([_, v]) => v != null)
.reduce((acc, [k, v]) => ({ ...acc, [k]: v }), {}) as {
[K in keyof T as T[K] extends null | undefined ? never : K]: T[K]
};

// Or
const removeNullUndefined = <T extends Record<string, any>>(obj: T) =>
Object.fromEntries(Object.entries(obj).filter(([_, v]) => v != null)) as {
[K in keyof T as T[K] extends null | undefined ? never : K]: T[K]
};
Examples
examples.js
removeNullUndefined({
foo: null,
bar: undefined,
fuzz: 42,
}); // { fuzz: 42 }

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Phước Nguyễn